Doing some practice on recursion and map implementation to knock some rust off Clojure. I’m using lists only here so how am I trying to mix seq and non-seqable stuff? REPL: Answer Some errors: replace ‘(finished-set) with finished-set into adds elements from one collection to another, I think you’re looking for conj (that’s the source of IllegalArgumentException) and if you’ll
Tag: casting
I can’t understand casting interface to children that don’t have any parents
I am studying lambda and then WebClient Class so I am creating bean of WebClient I think top codes and bottom codes are the same I don’t understand this cast situation because HttpMessageWriter is interface and LoggingCodecSupport is class but LoggingCodecSupport doesn’t implement HttpMessageWriter, so I think HttpMessageWriter can’t cast to LoggingCodecSupport This is the code of HttpMessageWriter This is
Cast exception when trying to get the resultset in hibernate “Cannot cast ‘java.lang.Object[]’ to”
In my application im using Hibernate 3.3 for the data connection. When im trying to get the resultset by a native query, it throws Cannot cast ‘java.lang.Object[]’ to org.model.Term exception. Model …
Enable a JButton when some component changed its border color [closed]
My goal is to enable a JButton only when some JTextFields and JComboBox change its border color from red to green. These components are included in three different JPanel. I try to create a function …
Why is this lambda expression cast using an ampersand?
recently I stumbled over the following code in the Java Comparator class: public static <T, U extends Comparable> Comparator comparing( Function<? super …
Integer parameters formula returns integer
Code below makes foo value as -1149239296 i. e. integer value which is out of bounds: Seems like Java takes type of first parameter and tryes to return formula’s result with that type. Where in Java specification one can read that story? I made such suggestion cause actually returns sets long value to foo. Answer For this case, casting any
Integer division: How do you produce a double?
For this code block: int num = 5; int denom = 7; double d = num / denom; the value of d is 0.0. It can be forced to work by casting: double d = ((double) num) / denom; But is there another way to …