If you try: Integer.valueOf(” 00″); …a java.lang.NumberFormatException is thrown. So, this is easy enough to fix by stripping any white space, even for a Java noob like me, but I’d very much …
I’m reading in a text file formated like So I need to keep try of whether I’m in a definition or not based on when I reach those emtpy lines. Thing is, BufferedReader discards n characters, and somehow comparing that empty line to String “” is not registering like I thought it would. How can I go about doing this.
There is a class trim() to remove white spaces, how about adding/padding? Note: ” ” is not the solution. Answer I think you are talking about padding strings with spaces. One way to do this is with string format codes. For example, if you want to pad a string to a certain length with spaces, use something like this: In
What regex pattern would need I to pass to java.lang.String.split() to split a String into an Array of substrings using all whitespace characters (‘ ‘, ‘t’, ‘n’, etc.) as delimiters?