How to split a string with any whitespace chars as delimiters

Tags: , , ,



What regex pattern would need I to pass to java.lang.String.split() to split a String into an Array of substrings using all whitespace characters (' ', 't', 'n', etc.) as delimiters?

Answer

Something in the lines of

myString.split("\s+");

This groups all white spaces as a delimiter.

So if I have the string:

"Hello[space character][tab character]World"

This should yield the strings "Hello" and "World" and omit the empty space between the [space] and the [tab].

As VonC pointed out, the backslash should be escaped, because Java would first try to escape the string to a special character, and send that to be parsed. What you want, is the literal "s", which means, you need to pass "\s". It can get a bit confusing.

The \s is equivalent to [ \t\n\x0B\f\r].



Source: stackoverflow