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Tag: lambda

Is there a way to convert a LambdaExpression to a String

I want to convert a LambdaExpression like pos -> pos.x < 5 && pos.y < 5 to a String which looks like this: “pos.x < 5 && pos.y < 5” Is this possible in Java? In C# I’m using something similar like this Answer No, it’s not possible. Java is compiled to a set of bytecode instructions. The exact form

Why use lambda over normal methods?

So suppose my application does lots of repetitive work, for example let’s say my application checks lots of various Lists if they’re empty or not. There are two methods by which I can accomplish this functionality – (there maybe other methods but since my goal is to understand the difference of the two methods and not the functionality itself here

Having trouble understanding the following Lambda method from Java 8

This Lambda 8 method came up in one of the suggested answers on leetcode.com: https://leetcode.com/problems/merge-intervals/discuss/21222/A-simple-Java-solution Below is the method I cannot seem to understand: I understand that the Arrays.sort() sorts the array in ascending order and the second argument is supposed to be the range it sorts the array. What I don’t understand is the i1 and i2 arguments and

Lambda expresions and “? :” operator in Java 14

Good day to everyone, I have a question regarding the usage of the ? : operator in the lambda expressions, especially in the switch statements. Could you kindly clarify, why the below code would not work and will be marked as Not a statement And the next one will. Is there a way to use the ? : operator in

Why is this lambda expression cast using an ampersand?

recently I stumbled over the following code in the Java Comparator class: What’s confusing me is the (Comparator<T> & Serializable) part. Since the method only returns a Comparator I don’t see the use in casting to Serializable. I also don’t see the reason to ever cast anything this way, or am I missing something? It seems to me that if

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