I want to convert a LambdaExpression like pos -> pos.x < 5 && pos.y < 5 to a String which looks like this: “pos.x < 5 && pos.y < 5” Is this possible in Java? In C# I’m using something similar like this Answer No, it’s not possible. Java is compiled to a set of bytecode instructions. The exact form
Tag: lambda
Why use lambda over normal methods?
So suppose my application does lots of repetitive work, for example let’s say my application checks lots of various Lists if they’re empty or not. There are two methods by which I can accomplish this functionality – (there maybe other methods but since my goal is to understand the difference of the two methods and not the functionality itself here
Lambda for comparing two lists of map id fields for missing ids
I have two lists of maps, and each map as an id field. I need to compare these two lists against one another to find missing ids from collectionB (“7777” in the below) I am really looking to learn more about stream() so any help with this would be appreciated. As you can tell I am not really sure where
Java 8 convert for loop and summing of values to stream/lambda?
I have some String inputs that I am looping over that I am trying to convert to java 8 stream/lambdas but was having some issues. My boilerplate code looks like this: I was trying to do something like … but couldn’t get the summ’ing logic down. could anyone point me in the right direction? Answer You need to apply first
Java 8 find element matching in a list of objects where each object has another object
I have two classes: I have a List<SampleClass> sampleClassList. I need to find the find element in the list which has a particular labelName and labelValue using Java 8. If I need to get the SampleClass object based on testString I would do, Now that the filtering involves Label class, I am unable to figure out how to do that.
Having trouble understanding the following Lambda method from Java 8
This Lambda 8 method came up in one of the suggested answers on leetcode.com: https://leetcode.com/problems/merge-intervals/discuss/21222/A-simple-Java-solution Below is the method I cannot seem to understand: I understand that the Arrays.sort() sorts the array in ascending order and the second argument is supposed to be the range it sorts the array. What I don’t understand is the i1 and i2 arguments and
Lambda expresions and “? :” operator in Java 14
Good day to everyone, I have a question regarding the usage of the ? : operator in the lambda expressions, especially in the switch statements. Could you kindly clarify, why the below code would not work and will be marked as Not a statement And the next one will. Is there a way to use the ? : operator in
Java 8 lambda expression or old way
Hello guys I’ve got question about Java 8 lambda expression. For example I want to delete following id from class. UserEntity userEntity = userEntityOptional.get(); for(Long permission_id : …
Why is this lambda expression cast using an ampersand?
recently I stumbled over the following code in the Java Comparator class: What’s confusing me is the (Comparator<T> & Serializable) part. Since the method only returns a Comparator I don’t see the use in casting to Serializable. I also don’t see the reason to ever cast anything this way, or am I missing something? It seems to me that if
How do you call a method from within a Collector in Java 8 Streaming?
I have a bit of code that is working functionally as I want it to: private Map