Here is the Java code to find the shortest concatenation of elements of Array wordBank to construct String Terget, using Dynamic Programming. Example: Input: wordBank = {“ab”, “c”, “d”, “abc”, “ad”}, Target = “abcd”. Output: {“abc”, “d”}. To do this, I have stored the combination of elements as an ArrayList in a HashMap. However, the hashMap does not store the
Tag: arraylist
Check if multiple objects have same value of a field in java and remove duplicates based on other fields
So I have a list of objects. Suppose they have 2 fields startDate, endDate(data type is timestamp). So if startDate is equal to startDate of another object then I have to choose the object with higher endDate. How can I achieve this efficiently. I can use 2 for loops but that would have a high time complexity. Any better way
Need a equivalent code in java streams for iterating list of Object
Can anyone help me with the stream equivalent code Note:- I cannot make the studentFinalList “final” Answer Some conditions in the code seem to be redundant and may be removed without affecting the logic: StringUtils.isBlank(ep.getName()) && ep.getName() == null may be shortened to ep.getName() == null – because StringUtils.isBlank checks for null, empty, or whitespace-only string StringUtils.isNotBlank(ep.getName()) && !ep.getName().equals(“”) &&
Sorting LinkedHashMap<String, ArrayList> by counting the occurrences in ArrayList problem
I have: How can i sort “maps” by counting the occurrences in “miss”? For example: miss => [3, 7] maps => {1=[0, 3, 6], 4=[2, 3, 4], 6=[0, 3, 7], 11=[1, 3, 6], 17=[2, 6, 11]} And i want to get: maps => {6=[0, 3, 7], 1=[0, 3, 6], 4=[2, 3, 4], 11=[1, 3, 6], 17=[2, 6, 11]} Answer The
How to get certain values from ArrayList and put them in a map
I have a program where there are 52 cards and int number of players (for example lets start from 4), the task is asking me to put elements like this in a map of Map<String, List>: I have written the logic like this: Any suggestions how to put those List in the map according to the task? Answer Since cannot
Create a list of List from an Array
How can i create a list of List from Array eg: int[] arr = {3, 1, 5, 8, 2, 4}. Such that the lists in the List have only two elements eg: [[3,1], [5,8], [2,4]]. So far i have tried code below but it return only lists with one element,I can’t figure out where i went wrong. Result: [[3], [1],
Append list according to their size in Java
I am trying to append two list according to their size. With list with bigger size in front. I have few lists like this. List<Pair<Double, String>> masterList = new ArrayList<>(); and this is the working Java code that I tried first – with a simple if else loop: I am fairly new to the Java, so I was studying about
java arraylist.add overwriting
I tried to add 1D ArrayList into 2D ArrayList like the following code, but the output was [34, 35, 36] [[34, 35, 36]] [4, 5, 6] [[4, 5, 6], [4, 5, 6]] <- the correct output would be [[34, 35, 36], [4, 5, 6]]. the previous one was overwritted, how can I solve this problem? Answer You put the array
Print a string from ArrayList of String[] per Index?
How to print ArrayList of String[] into String per index with expected Output like this Here is the code and how to print it? Answer You were pretty close to it: This generates your String to be outputted. Printing: Just don’t forget to initialize yourArrayList prior of the method call.
Merge an List of Object and an Object to a new array in Java [closed]
Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 10 months ago. Improve this question I have List<BigInteger> sample1 = Lists.newArrayList(BIGINTEGER1, BIGINTEGER2,BIGINTEGER3); I have to create new List sample2 with one more value BIGINTEGER4 along with sample1 list: How can