If both House() and House(name) are called then why is not “Building” printed two times, but instead one time? Output: Answer House(String name) calls this() which is the same as House(). House() implicitly calls super() which is the same as Building(). You never call Building(String name). House(String name) could call super(name) to do that.
Tag: this
Using ‘this’ in constructor and other methods in Java – when is it OK to skip it?
I’m new to Java, so forgive me if it’s a stupid question. I tried to find a clear answer on this forum but with no joy. I know what ‘this’ is. It know it refers to an actual instance and helps narrow …
Why can I not use “super” variable from a static context, even though “super” refers to the parent class and NOT a class instance, unlike “this”?
I’m talking java language. Variable “this”, when used inside a class, refers to the current instance of that class, which means you cannot use “this” inside a static method. But “super”, when used inside a class, refers to the superclass of that class, not an instance of the superclass, which should mean that you can use “super” inside a static
C++ equivalent to Java this
In Java you can refer to the current object by doing: this.x = x. How do you do this in C++? Assume that each of these code examples are part of a class called Shape. Java: C++: Answer Same word: this Only difference is it is a pointer, so you need to use the -> operator: