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Tag: json

GROOVY I am getting random backslashes when creating JSON file in Folder

I am having trouble compiling the JSON file. This is my method (the main method just has the name of the method I am writing this code in it so I did not include the main method in here.) my output in the console does come out right like this [commands:[{“includeCommandName”:true,”path”:”${BUILTIN_EXE(command)}”,”name”:”upload”},{“includeCommandName”:true,”path”:”${BUILTIN_EXE(command)}”,”name”:”file_info”}]] but sending it to the JSON file it comes

Jackson cannot parse body of a POST request

I am using Spring Boot to implement two web services, User and Book, and I am implementing the POST methods. When I send a POST request, i include the hard-coded JSON object in the HTTP Body: I am working at the same time on the two services, and while the creation of the “user” object works fine, Jackson throws an

Serialize and Deserialize Java object having vavr list

I have a Java object with vavr list. When I serialize the object objectwriter.writeValueAsString(currentDossier) and print the values then in the JSON output I see, where remarks is a vavr list field inside the object. Now if I try to deserialize the same value into the object objectMapper.readValue(json, Customer.class) then I get error: Why is the seralized JSON text not

Get json object in Array based on key and value in Java

I have a Json body like the example below. I need to extract the value from a key that has another key with a specific value in an array. I am passing in a JsonNode with everything in the detail component of the message, I can easily extract from each level, however, I’m struggling with the array. In this case,

JSON file not copied to target folder

In my java project, I have a .json file which I have placed in resource folder. When I am trying to read this .json file in my main class using the getResourceAsStream() method, I am getting a FileNotFoundException. I checked that under folder target > classes this .json file is not present. I am not sure why this .json file

Adding custom arguments to Jackson deserializer

I have a custom deserializer. But I want to be able to pass additional arguments. For example How can I pass in my custom parameter on the annotation? Answer You cannot add your own parameters to @JsonDeserialize, because you can’t alter Jackson’s implementation of this annotation. However, you can achieve your goal in a slightly different way. You can invent

Pulling data from json inside mysql to java

So I have a claim script that I’m trying to put together, that claims the product after purchase. The program is built inside of Java. The problem I’m running into is that there is a custom field they input on their purchase, and the store itself inserts it into a JSON format. So I need to execute a query that

What is the best way to define a common Base Java Model for all Responses?

I have a need to format all REST responses as: Where the response is an arbitrary data (object, array; with arbitrary fields) different for each REST API endpoint. What is the best way to define different response for each response Model ? I tried this (and it works, but I’m not sure is it the right thing to do): BaseResponseModel.java

Deserialising JSON array using RestTemplate

I’m trying to convert JSON data to a java class using Rest Template. The JSON data has this format and cannot be changed: The java class to save the data is: To receive the JSON data and deserialize i’m doing: But i’m getting this exception: I’ve done this before and it worked, but the JSON data had a slightly different

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