I have the following controller. The following line works just fine: user = userRepository.selectUserByLogin(name); It correctly returns the user. Now I want to move that code to a getLoggedUser method of a “Utilities” class. This is how I did it. Controller Utilities But when that is executed I’m getting the following error: Cannot invoke “UserRepository.selectUserByLogin(String)” because “this.userRepository” is null. Why
Tag: spring-mvc
Spring MVC – JSP files for various controllers to be more generic
I have a java spring MVC project with various controllers. These controllers have the functionality to add, edit, delete configurations. The JSP files for these various controllers are almost same (…
Only Post REST api is working , PUT,GET,DELETE api’s are not working in spring boot application
i have created CRUD api with Spring boot.But Only POST api is working fine. PUT,GET and DELETE api is not working. model controller **The Response i’m Getting For the api’s is ** { “timestamp”: “2020-12-26T16:03:32.723+00:00”, “status”: 500, “error”: “Internal Server Error”, “message”: “”, “path”: “/customers” } Error in Console Answer seems already a tip in log: No default constructor for
Why do MockMvc tests suggest injecting WebApplicationContext @BeforeEach test?
So the reference documentation suggests why not do it as constructor injection instead? (I haven’t tried this, I’m just assuming it doesn’t immediately blow up) Answer Whether you choose constructor injection, method injection, or field injection is a matter of taste when using JUnit Jupiter with the SpringExtension. The example in the reference manual simply shows one way to do
Java find Object which not containing in List of object
I wondering is there any way to filter object array with another object array. Its is to hard to explain but ill try my best this is my first entity this is second entity i have two list of this each entities Like this And I need to get MDynamicFieldTypes list which not containing in dynamicFields->type List and add fake
How to hide/show thymeleaf fields based on controller condition?
I have a Spring MVC application with thymeleaf. Depending on a condition tested in the controller method I want to show or hide an html element from the view (input, span, div, button…). How to do that? For instance, in asp.net you can do myButton.Visible = false (or true) if you want or don’t want to display it. Anything like
How to print in console in Spring MVC application(Dynamic web project)?
I have a Dynamic Web app in Eclipse which has a normal Controller, Entity and a DAO class. I am using Hibernate to get the data from the database and then displaying it in JSP page. But when I try to use System.out.print(); in Controller class to see weather my data is being fetched from the database it is not
Bad Request from saving structured JSON object
I have created a simple web REST application that has to save a “change ticket” to database. But after I try to create a POST request with JSON as body I get an error: I am using Spring Boot 2, MySQL as DB and MapStruct to convert DTO to entities and vice versa. Also I use Project lombok to get
How do I avoid the white label error(404) on localhost:8080?
I have been looking around here and in other forums for hours and I still haven’t found what I am doing wrong. I have built a simple Spring-Boot application with MongoDB and I have no errors in the console when i run it but i keep getting the white label error no matter what I do. My main and controller
spring boot security not configured properly
I am new to Spring boot and Spring boot security. However, using the existing sample codes, I had written a code which worked correctly. In my design, I had a separate page for my login, called login….