I’ve already tried adding the matcher.find() and matcher.matches() in order to query matching string values, but still its not working. I am trying to have 3 group patterns to match, and for my example here, I want to match and find group 1 of pattern enclosed in the first round parenthesis. Why is the grp1 not being retrieved?, afaik this
Tag: regex
Split a java string among brackets, including the brackets, but only if no space between brackets
I need to be able to turn a string, for instance “This and <those> are.”, into a string array of the form [“This and “, “<those>”, ” are.”]. I have been trying to using the String.split() command, and I’ve gotten this regex: “(?=[<>])” However, this just gets me [“This and “, “<those”, “> are.”]. I can’t figure out a good
Split strings in Java using RegEx
I want to split String a = “1.48 kb”; in java. Output is 1.4 But I want output: 1.4 kb Answer You can try using this:
How to remove more than one match in Java using replaceAll()?
Hi there I am trying to remove two or more words in a String with the replaceAll method in Java but I am not good in regex at all and I have not been able to do it. So, here is the code: But when I run this what I get is the following text menu-eet brton-ontent By the way
Why can’t I make a group repeat in regex Java?
I have a regex I want to construct for validating the UNC syntax, which is: \serversharedfolderpath I don’t care about the server or folder characters, I exclusively want to validate the thing1thing2maybe3 syntax, the server and folder names will be validated separately. This is what I have so far: These are my tests: MATCH – \servermultiplefoldersexamplepath FAIL – \server\multiplefoldersexamplepath SHOULD
How to make a regular expression for this seemingly simple case?
Is it possible to write a regular expression that works with String replaceAll() to remove zero or more spaces from the end of a line and replace them with a single period (.). For example, a regex that will make these (non-exhaustive) test cases pass: I know I can do it with replaceFirst(” *$”, “.”), but I’m wondering if it
Complex splitting of a String using REGEX, only discarding spaces
In Java (JDK 11), consider the following string: I am trying to come up with a RegEx that will split anything that isn’t a digit, whilst keeping the separators except space. So in the above example, I would like to end up with the following array: Do note the leading zeroes in 006, and -7. The code I am using
Regex split string in double quotes
I have the following string I need to split by double quotes. below is the sample string When I try to split the string by double quotes, knowing that some quotes can be empty I tried the following : String[] split = raw.split(“”(\w\s+|\s+)””); it is close but I seem to be missing something. Answer You can simply split it on
how pattern syntax exception works
how do I use the following statement in try n catch block to chk if the name is valid and display error msg if any? and how to use PatternSyntaxException Answer You don’t need a try…catch to check if the name is valid. The line you wrote: NAME_PATTERN.matcher(name).matches() returns a boolean, true if it matches and false if it doesn’t.
Remove backslash before forward slash
Context: GoogleBooks API returing unexpected thumbnail url Ok so i found the reason for the problem i had in that question what i found was the returned url from the googlebooks api was something like this: Going to that url would return a error, but if i replaced the ” /”s with “/” it would return the proper url is