This is what I tried: the error that I get is ‘ Runner org.junit.internal.runners.ErrorReportingRunner (used on class com.unibuc.AWBD_Project_v1.services.ServiceTest) does not support filtering and will therefore be run completely. Test class should have exactly one public zero-argument constructor’ Here is the LocationService: Answer Hello there is 3 issues in your test code. 1 you should remove the EntityManager entityManager from your
Tag: jpa
Failed to read candidate component class when testing Spring Data Repository – IndexOutOfBoundsException
I’m trying to test a Spring Data JPA repository but when I run the test I always get the following error The class it talks about is a pretty simple entity If I comment the @Table annotation I get the same error on the next class. I also had the issue on a classe with @Cacheable and it gave me
JPA Specification for Enum
My JPA Entity as an Enum field Where If I add a where condition with a specification what is the correct way to include Enums into Specification queries? Answer Try doing this:
JPQL issue updating records
Trying to update a record in a database but getting this error: Code below is responsible for inserting it Im not sure if there is a type issue with propId being a Long or if i have written the SQL paths wrong or both. Answer You’re trying to execute an SQL query as JPQL. There are a couple options to
Saving entity with Spring JPA Repository resets enum ttype value
I have an TimelineEntity entity, that uses HoTimelineType enum with custom integer value. That custom integer value is stored in the database. Implemented via Using @PostLoad and @PrePersist Annotations Sprint JPA Repository is used to save and get entities. Here is the issue: When the newTE entity is saved, prePersist is invoked, and inside this method, the hoTimelineType is null
Criteria API join with filter
So I am trying to replace the following native SQL with JPA Criteria Api: or The entities look a bit like this: I implemented a org.springframework.data.jpa.domain.Specification I can use together with a JpaSpecificationExecutor like: and But I only get one side of the join/select like: when I do: How do I add the table to the select here? So the
Spring Data Jpa: persisting child entities from parent entity does not update child identity
Environment: OS: Ubuntu 20.04 LTS Java: OpenJDK 17.0.3 Spring Boot: 2.6.7 MySQL: 8.0.29 Is it normal for Spring Data Jpa (or Jpa in general) to NOT update child identity attributes when the child is persisted (saved) via the parent entity repository? Consider this: When I call someClassFunction() I get: The database assigned id is NOT available to me immediately. I
Update statement is no query?
How do I define the update statement in the orm.xml. I have it as a named-query and everything works, but my teacher said that an update statement isn’t a query. I have tried a native query, but that wasn’t working. ORM-Type: Update Statement: Answer The term “query” is used rather ambiguously. Some people interpret it literally as “asking for information”,
How to save array of object in sprig boot with crudrepository?
I am very new to Spring boot and this is my first spring dummy project where I’m trying to learn to save an array of objects in mysql-db. Actually, I am trying to use the saveAll method from the crudRepository in my controller. But it’s giving me an error no instance(s) of type variable(s) S exist so that Iterable<S> conforms
Create custom finder with spring
I trying to implement a database with a many-to-many relationship.The database has been built, now we need queries to it. I’m using this article as an example: https://www.bezkoder.com/jpa-many-to-many/. When I create custom finder in Repository – server crushes at running. I have two Entity: MassageEntity and RstringsEntity. I’m trying to create a method List<MasageEntity> findMasageEntitiesByRstringsEntitiesId(Long string_id);. Without that method server