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Hibernate mapping between PostgreSQL enum and Java enum

Background

  • Spring 3.x, JPA 2.0, Hibernate 4.x, Postgresql 9.x.
  • Working on a Hibernate mapped class with an enum property that I want to map to a Postgresql enum.

Problem

Querying with a where clause on the enum column throws an exception.

org.hibernate.exception.SQLGrammarException: could not extract ResultSet
... 
Caused by: org.postgresql.util.PSQLException: ERROR: operator does not exist: movedirection = bytea
  Hint: No operator matches the given name and argument type(s). You might need to add explicit type casts.

Code (heavily simplified)

SQL:

create type movedirection as enum (
    'FORWARD', 'LEFT'
);

CREATE TABLE move
(
    id serial NOT NULL PRIMARY KEY,
    directiontomove movedirection NOT NULL
);

Hibernate mapped class:

@Entity
@Table(name = "move")
public class Move {

    public enum Direction {
        FORWARD, LEFT;
    }

    @Id
    @Column(name = "id")
    @GeneratedValue(generator = "sequenceGenerator", strategy=GenerationType.SEQUENCE)
    @SequenceGenerator(name = "sequenceGenerator", sequenceName = "move_id_seq")
    private long id;

    @Column(name = "directiontomove", nullable = false)
    @Enumerated(EnumType.STRING)
    private Direction directionToMove;
    ...
    // getters and setters
}

Java that calls the query:

public List<Move> getMoves(Direction directionToMove) {
    return (List<Direction>) sessionFactory.getCurrentSession()
            .getNamedQuery("getAllMoves")
            .setParameter("directionToMove", directionToMove)
            .list();
}

Hibernate xml query:

<query name="getAllMoves">
    <![CDATA[
        select move from Move move
        where directiontomove = :directionToMove
    ]]>
</query>

Troubleshooting

  • Querying by id instead of the enum works as expected.
  • Java without database interaction works fine:

    public List<Move> getMoves(Direction directionToMove) {
        List<Move> moves = new ArrayList<>();
        Move move1 = new Move();
        move1.setDirection(directionToMove);
        moves.add(move1);
        return moves;
    }
    
  • createQuery instead of having the query in XML, similar to the findByRating example in Apache’s JPA and Enums via @Enumerated documentation gave the same exception.
  • Querying in psql with select * from move where direction = 'LEFT'; works as expected.
  • Hardcoding where direction = 'FORWARD' in the query in the XML works.
  • .setParameter("direction", direction.name()) does not, same with .setString() and .setText(), exception changes to:

    Caused by: org.postgresql.util.PSQLException: ERROR: operator does not exist: movedirection = character varying
    

Attempts at resolution

  • Custom UserType as suggested by this accepted answer https://stackoverflow.com/a/1594020/1090474 along with:

    @Column(name = "direction", nullable = false)
    @Enumerated(EnumType.STRING) // tried with and without this line
    @Type(type = "full.path.to.HibernateMoveDirectionUserType")
    private Direction directionToMove;
    
  • Mapping with Hibernate’s EnumType as suggested by a higher rated but not accepted answer https://stackoverflow.com/a/1604286/1090474 from the same question as above, along with:

    @Type(type = "org.hibernate.type.EnumType",
        parameters = {
                @Parameter(name  = "enumClass", value = "full.path.to.Move$Direction"),
                @Parameter(name = "type", value = "12"),
                @Parameter(name = "useNamed", value = "true")
        })
    

    With and without the two second parameters, after seeing https://stackoverflow.com/a/13241410/1090474

  • Tried annotating the getter and setter like in this answer https://stackoverflow.com/a/20252215/1090474.
  • Haven’t tried EnumType.ORDINAL because I want to stick with EnumType.STRING, which is less brittle and more flexible.

Other notes

A JPA 2.1 Type Converter shouldn’t be necessary, but isn’t an option regardless, since I’m on JPA 2.0 for now.

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Answer

HQL

Aliasing correctly and using the qualified property name was the first part of the solution.

<query name="getAllMoves">
    <![CDATA[
        from Move as move
        where move.directionToMove = :direction
    ]]>
</query>

Hibernate mapping

@Enumerated(EnumType.STRING) still didn’t work, so a custom UserType was necessary. The key was to correctly override nullSafeSet like in this answer https://stackoverflow.com/a/7614642/1090474 and similar implementations from the web.

@Override
public void nullSafeSet(PreparedStatement st, Object value, int index, SessionImplementor session) throws HibernateException, SQLException {
    if (value == null) {
        st.setNull(index, Types.VARCHAR);
    }
    else {
        st.setObject(index, ((Enum) value).name(), Types.OTHER);
    }
}

Detour

implements ParameterizedType wasn’t cooperating:

org.hibernate.MappingException: type is not parameterized: full.path.to.PGEnumUserType

so I wasn’t able to annotate the enum property like this:

@Type(type = "full.path.to.PGEnumUserType",
        parameters = {
                @Parameter(name = "enumClass", value = "full.path.to.Move$Direction")
        }
)

Instead, I declared the class like so:

public class PGEnumUserType<E extends Enum<E>> implements UserType

with a constructor:

public PGEnumUserType(Class<E> enumClass) {
    this.enumClass = enumClass;
}

which, unfortunately, means any other enum property similarly mapped will need a class like this:

public class HibernateDirectionUserType extends PGEnumUserType<Direction> {
    public HibernateDirectionUserType() {
        super(Direction.class);
    }
}

Annotation

Annotate the property and you’re done.

@Column(name = "directiontomove", nullable = false)
@Type(type = "full.path.to.HibernateDirectionUserType")
private Direction directionToMove;

Other notes

  • EnhancedUserType and the three methods it wants implemented

    public String objectToSQLString(Object value)
    public String toXMLString(Object value)
    public String objectToSQLString(Object value)
    

    didn’t make any difference I could see, so I stuck with implements UserType.

  • Depending on how you’re using the class, it might not be strictly necessary to make it postgres-specific by overriding nullSafeGet in the way the two linked solutions did.
  • If you’re willing to give up the postgres enum, you can make the column text and the original code will work without extra work.
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