I have an ArrayList in Java and each element in the list is an object with 3 fields (a, b and c). I should order by a in ascending order; if 2 elements have the same value for a, they should be ordered by b in descending order; finally, if 2 elements have the same value even for b, they
Tag: lexicographic-ordering
Given 2 strings, remove only one digit to make 1 string lexicographically smaller
I am trying to work through a coding problem of string manipulation in Java. The question is that Given two strings S and T consisting of digits and lowercase letters, you are allowed to remove only one digit from either string, count how many ways of removal to make S lexicographically smaller than T. I came up with this test
What is the equivalent way to do Ordering.lexicographical() in Java 8 Comparator?
Is there a way to implement Ordering.lexicographical() with Java 8 Comparator? Comparator.thenCompare seems to be limited in this Answer Seemingly not, no. As a result, Guava still provides this functionality, but in the new class Comparators: https://guava.dev/releases/snapshot/api/docs/com/google/common/collect/Comparators.html#lexicographical(java.util.Comparator). Note that Guava generally does a good job telling you whether and how to migrate off of it to new Java features, so
String Comparison in Java
What does “compare two strings lexicographically” mean? Answer Leading from answers from @Bozho and @aioobe, lexicographic comparisons are similar to the ordering that one might find in a dictionary. The Java String class provides the .compareTo () method in order to lexicographically compare Strings. It is used like this “apple”.compareTo (“banana”). The return of this method is an int which