# Java If-Else in HackerRank, Is my code good or can I get better solution for the problem

Problem Statement

Given an integer,n, perform the following conditional actions:

If n is odd, print Weird If n is even and in the inclusive range of 2 to 5, print Not Weird If n is even and in the inclusive range of 6 to 20, print Weird If n is even and greater than 20, print Not Weird Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer,n.

Constraints

1<=n<=100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: n=3 n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n=24 n>20 and n is even, so it isn’t weird. Thus, we print Not Weird.

My solution to the problem.

```import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args) {
int N = scanner.nextInt();
scanner.skip("(rn|[nru2028u2029u0085])?");
if(N%2==0){
if(N>1){
if(N<6){
System.out.println("Not Weird");
}
else if(N<21){
System.out.println("Weird");
}
else{
System.out.println("Not Weird");
}
}
}
else{
System.out.println("Weird");
}

scanner.close();
}
}
```

Can I get suggestions regarding the solution. Thank You.

The conditions should be merged: the result is `Weird` for any number in the range `6 <= n <= 20` OR n is odd, otherwise it is `Not Weird`:
```System.out.println((6 <= n && n <= 20 || n % 2 != 0) ? "Weird" : "Not Weird");