Java equivalent of this JavaScript regex code?

I have this JavaScript code:

highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replace(/[\;]/g, ' ');
highlightTerm = highlightTerm.replace(/([{}<>/=:])(?=(?:[^"]|"[^"]*")*$)/g, '\$&');
highlightTerm = highlightTerm.replace(/"/g, '"');
highlightTerm = highlightTerm.trim();

console.log(highlightTerm); // "h=e ?l*l{o"

I am trying to find the Java equivalent. I’ve tried the following bit it gives a different result:

String highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replaceAll("[\;]", " ");
highlightTerm = highlightTerm.replaceAll("([{}<>\/=:])(?=(?:[^"]|"[^"]*")*$)", "\$&");
highlightTerm = highlightTerm.replaceAll("["]", "\"");
highlightTerm = highlightTerm.trim();

System.out.println(highlightTerm); // "h=e ?l*l{o"

Any help is much appreciated!

Answer

The problem you are having is that '\$&' is Javascript mean whole matched string but doesn’t mean the same in Java. I don’t think there is a one-line solution in Java to solve this problem, but this code should work:

String highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replaceAll("[\;]", " ");
//highlightTerm = highlightTerm.replace(/([{}<>/=:])(?=(?:[^"]|"[^"]*")*$)/g, '\$&');

//These lines are replacement for the above line
Pattern pattern = Pattern.compile("([{}<>\/=:])(?=(?:[^"]|"[^"]*")*$)");
Matcher matcher = pattern.matcher(highlightTerm);

StringBuilder builder = new StringBuilder();
int i = 0;
while (matcher.find()) {
    String replacement = "\" + matcher.group(1);
    builder.append(highlightTerm, i, matcher.start());
    builder.append(replacement);
    i = matcher.end();
}
builder.append(highlightTerm.substring(i));
highlightTerm = builder.toString();

//rest of your code
highlightTerm = highlightTerm.replaceAll("["]", "\"");
highlightTerm = highlightTerm.trim();

System.out.println(highlightTerm);