Insert embeded document without reading whole document – spring, mongo

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I have this factory collection :

@Document(collection = "factory")
public class Factory
{
    Private List<Product> products;

}

which embeds the Product as products. When I have to add a product to an existing factory :

@Autowired
private FactoryRepository factoryRepository;

public void addProduct(Long id, Product product) {
    Factory f = factoryRepository.findById(id);
    f.addProduct(product);
    factoryRepository.save(f);

}

However, the issue is that product is a large object which contains a set of heavy attributes and the factory can have 2000 products.

So, the retrieved factory causes large memory consumption although it is not required in this phase. Is there a way to append a new product object directly into the factory document without reading the whole object?

EDIT:

As for the comments, I tried :

public void addProduct(Long id, Product product) {
        Document find = new Document("_id",id);
        Document listItem = new Document("products",product);
        Document push = new Document("$push", listItem);
        collection.updateOne(find,push);
}       

This gives error :

org.bson.codecs.configuration.CodecConfigurationException: Can't find a codec for class product

So I modified to convert it to a string before push :

public void addProduct(Long id, Product product) {
        Document find = new Document("_id",id);
        ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
        Document listItem = new Document("products",ow.writeValueAsString(product));
        Document push = new Document("$push", listItem);
        collection.updateOne(find,push);
}     

This pushed object correctly but when reading :

org.springframework.core.convert.ConverterNotFoundException: No converter found capable of converting from type [java.lang.String] to type [Product]

Still, I got nowhere here. Any ideas on fixing this issue?

Answer

You should use MongoTemplate to update product with push to add to existing products. Something like

package com.example.demo;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.ApplicationRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.Bean;
import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.core.mapping.Document;
import org.springframework.data.mongodb.core.query.Criteria;
import org.springframework.data.mongodb.core.query.Query;
import org.springframework.data.mongodb.core.query.Update;

import java.util.List;

@SpringBootApplication
public class So62173077Application {

    public static void main(String[] args) {
        SpringApplication.run(So62173077Application.class, args);
    }

    @Autowired
    private MongoTemplate mongoTemplate;

    @Document(collection = "factory")
    public class Factory
    {
        private Long id;
        private List<Product> products;

    }

    public Long createFactory() {
        Factory factory = new Factory();
        factory.id = 1L;
        return mongoTemplate.insert(factory).id;
    }

    public void addProduct(Long id) {
        Query query = new Query();
        query.addCriteria(Criteria.where("id").is(id));
        Update update = new Update();
        Product product = new Product();
        product.name = "stackoverflow";
        update.push("products", product);
        mongoTemplate.updateFirst(query, update, Factory.class);
    }

    private class Product {
        private String name;
    }

    @Bean
    public ApplicationRunner runner() {
        return args -> {
            //Long id = createFactory();
            addProduct(1L);

        };
    }

}


Source: stackoverflow