How to obtain the last number different to zero in an array in Java

I have for example this array:

double array1[] = {2.3, 5.0, 4.7, 8.2, 1.8, 9.0, 0, 0, 0, 0, 0, 0};

And I want to find the last number of the array different to 0. In this case, my output should be: 9.0

My code is:

double array1[] = {2.3, 5.0, 4.7, 8.2, 1.8, 9.0, 0, 0, 0, 0, 0, 0};
double array2[] = array1.length;
double num;

for (int i = 0; i < array1.length; i++){
    array2[i] = array1[i];
    if(array2 != 0){
        num = array[i-1];
    }
} 

But it doesn’t work.

I need to highlight that the size of the array1 is always the same. But the non-zero numbers can change, in any case, all the zeros will be at the end of the array always.

I need also have array2, obtained by array1.

Furthermore, all the numbers are always positive.

Answer

Here is one way using a loop and the ternary operator (a ? b : c says if a is true return b, else return c)

double array1[] = {2.3, 5.0, 4.7, 8.2, 1.8, 9.0, 0, 0, 0, 0, 0, 0};

• initialize last to 0.
• iterate over array
• if current value (i) == 0, return last.
• else return i

double last = 0;
for(double i : array1) {
    last = i == 0 ? last : i;
}
System.out.println(last);

prints 9.0