String str = "abc";
Comparing this string variable like the following.
if(str.equals("abc")) {}
In case str
is null
, it will cause a java.lang.NullPointerException
to be thrown as obvious.
To avoid that, an additional null check may be enforced. Such as,
if(str != null && str.equals("abc")) {}
I find it plain ugly. Better could be rewritten as follows.
if("abc".equals(str)) {}
This will never throw a java.lang.NullPointerException
even though str
is null
. Besides, object equals null
is never true.
The last case however, cannot be used, when the conditional expression is inverted like so,
if(!"abc".equals(str)) { System.out.println(str.length()); }
This will cause a java.lang.NullPointerException
inside the if
block, if str
is null
.
Can this somehow be avoided without rewriting the conditional statement like the following?
if(str != null && !"abc".equals(str)) {}
This is plain ugly and unreadable.
Although the example uses a String
object, it may be a more complex object.
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Answer
Long story short : There is simply no library method doing this which I know of. This if(str != null && !"abc".equals(str)) {}
actually requires that both the objects to be compared are not null
and not equal to each other.
A static utility method performing this task is sufficient to deal with.
/** * Returns {@code true} if and only if both the arguments (objects) are * <b>not</b> {@code null} and are not equal to each other and {@code false} * otherwise. * * @param a an object. * @param b an object to be compared with {@code a} for equality. * @return {@code true} if both the arguments (objects) are <b>not</b> {@code null} * and not equal to each other. */ public static boolean notEquals(Object a, Object b) { return (a == b || a == null || b == null) ? false : !a.equals(b); }