import java.util.*; public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.print("Enter the size ??"); int n = sc.nextInt(); int[] marks = new int[n + 1]; for (int i = 0; i < n; i++) { System.out.println("Enter " + i + " number ??"); marks[i] = sc.nextInt(); } System.out.println("The following numbers are : "); for (int j = 0; j < marks.length - 1; j++) { System.out.println(marks[j] + " "); } int max = marks[0]; int min = marks[0]; int s = marks.length; for (int i = 0; i < s; i++) { if (marks[i] > max) { max = marks[i]; } if (marks[i] < min) { min = marks[i]; } } System.out.println("Max is " + max + " Min is " + min); }
Output:
Enter the size ??2 Enter 0 number ?? 56 Enter 1 number ?? 56 The following numbers are : 56 56 Max is 56 Min is 0
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Answer
Hello and welcome to StackOverflow. Next time, febore you jump into the internet for help, please try this approach. It will solve your problem much quicker.
for (int i = 0; i < s; i++) { System.out.println("DEBUG: number in index " + i + " is " + marks[i]); if (marks[i] > max) { System.out.println("DEBUG: number is greater than current max " + max); max = marks[i]; } if (marks[i] < min) { System.out.println("DEBUG: number is smaller than current min " + min); min = marks[i]; } }
This process is called “debugging”. It can be done by adding spurious amount of logging like above or by stepping through the code with a debugger.