Reversing digits in 2D array

I was trying to reverse the numbers in this 2D array, but I happened to be reversing only first and the last numbers.

So far I have done this, but don’t know where is the mistake and how to fix it, so that every digits are being reversed, not just first and the last:

int [][] array = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
        
        int x = 0, y = array.length - 1;
        int a = 0, b = array[y - 2].length - 1;
        int temp; 
        
        while(x < y && a < b)
        {
          temp = array[x][a]; 
          array[x][a] = array[y][b]; 
          array[y][b] = temp;
          a++; b--;
          
          if(a == 3 && b == 0)
          {
              a = 0;
              x++; y--;
          } 
        }

        
        for(int i=0; i<array.length; i++)
        {
            for(int j=0; j<array[i].length; j++)
            {
                System.out.println(array[i][j]);
            }
        }

Answer

Ok, here is another way that doesn’t require using Collections. It does use Arrays.deepToString() for displaying the results.

• All reverse methods shown here only require iterating across half the array. This works whether the array has an even or odd number of values.
• first, reverse the array of arrays.
• then during that process, reverse the individual rows, going outside in as the main array is reversed. A helper method reduces code duplication
• If the array is of odd length, call the reverse method once more on the middle array.
• This also works independent of the size of each array.

int[][] array = { { 1, 2, 3, 4, 5 }, { 6, 7, 8 }, { 9 },
        { 10, 11, 12 } };

System.out.println("Before: " + Arrays.deepToString(array));

Now the driver code.

int len = array.length;
    
for (int i = 0; i < len / 2; i++) {
    int[] s = array[i];
    array[i] = array[len - i - 1];
    array[len - i - 1] = s;
    reverse(array[i]);
    reverse(array[len - i - 1]);
}
if (len % 2 == 1) { 
    reverse(array[len/2]);
}   
System.out.println("After:  " + Arrays.deepToString(array));

output

Before: [[1, 2, 3, 4, 5], [6, 7, 8], [9], [10, 11, 12]]
After:  [[12, 11, 10], [9], [8, 7, 6], [5, 4, 3, 2, 1]]

The helper method.

public static void reverse(int[] v) {
    int len = v.length;
    for (int i = 0; i < len / 2; i++) {
        int t = v[i];
        v[i] = v[len - i - 1];
        v[len - i - 1] = t;
    }
}