With regex in Java, I want to write a regex that will match if and only if the pattern is not preceded by certain characters. For example:
String s = "foobar barbar beachbar crowbar bar ";
I want to match if bar
is not preceded by foo
. So the output would be:
barbar beachbar crowbar bar
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Answer
You want to use negative lookbehind
like this:
w*(?<!foo)bar
Where (?<!x)
means “only if it doesn’t have “x” before this point”.
See Regular Expressions – Lookaround for more information.
Edit: added the w*
to capture the characters before (e.g. “beach”).