I am trying to write a program that outputs a Z pattern that is n
number of *
across the top, bottom, and connecting line using for loops.
Example:
JavaScript
x
Enter a number: 6
******
*
*
*
*
******
This is my current code, it’s producing a half pyramid upside down.
JavaScript
import java.util.*;
public class ZShape {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = input.nextInt();
for (int x = 0; x <= n; x++) {
for (int y = n; y >= 1; y--) {
if (y > x) {
System.out.print("* ");
}
else
System.out.print(" ");
}
System.out.println();
}
}
}
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Answer
This is the logic in the following code:
- Loop over each row of the output (so from 0 to
n
excluded so that we haven
rows) - Loop over each column of the output (so from 0 to
n
excluded so that we haven
columns) - We need to print a
*
only when it is the first row (x == 0
) or the last row (x == n - 1
) or the column is in the opposite diagonal (column == n - 1 - row
)
Code:
JavaScript
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = input.nextInt();
for (int row = 0; row < n; row++) {
for (int column = 0; column < n; column++) {
if (row == 0 || row == n - 1 || column == n - 1 - row) {
System.out.print("*");
} else {
System.out.print(" ");
}
}
System.out.println();
}
}
Sample output for n = 6
:
JavaScript
******
*
*
*
*
******
(Note that this output has trailing white-spaces for each row, you did not specify whether they should be included, but it is easy to remove them by adding another check).