I have a JSON as follows
[ { "a": "John", "id": "6", "c": "val1" }, { "a": "Jack", "id": "6", "c": "val2" }, { "a": "Joe", "id": "6", "c": "val3" } ]
I need to convert it into a Map<String, String> such that the values of the fields ‘a’ become the key and the values of the fields ‘c’ become the value in the Map.
In other words, my Map should look like the below:
John:val1 Jack:val2 Joe:val3
What is the shortest way to do this?
Also, I was wondering if in any way RestAssured GPath can be leveraged here
Something like this –
new JsonPath(jsonPayload).getString("findAll { json -> json.id == '6' }.a");
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Answer
You can use jackson
for example:
<dependency> <groupId>com.fasterxml.jackson.core</groupId> <artifactId>jackson-databind</artifactId> <version>2.13.2.2</version> </dependency>
I would create a wrapper for the resulting Map
and a custom deserializer.
@JsonDeserialize(using = MapWrapperDeserializer.class) public class MapWrapper { private final Map<String, String> map; public MapWrapper(Map<String, String> map) { this.map = map; } public Map<String, String> getMap() { return this.map; } }
The deserializer:
public class MapWrapperDeserializer extends StdDeserializer<MapWrapper> { public MapWrapperDeserializer() { super(MapWrapper.class); } @Override public MapWrapper deserialize(JsonParser parser, DeserializationContext context) throws IOException { JsonNode array = parser.getCodec().readTree(parser); int size = array.size(); Map<String, String> map = new LinkedHashMap<>(size); for (JsonNode element : array) { String key = element.get("a").asText(); String value = element.get("c").asText(); map.put(key, value); } return new MapWrapper(map); } }
A simple test:
public class Temp { public static void main(String[] args) throws Exception { ObjectMapper mapper = new ObjectMapper(); InputStream dataStream = getInputStreamOrJsonString(); MapWrapper wrapper = mapper.readValue(dataStream, MapWrapper.class); System.out.println(wrapper.getMap()); } }