I just want to remove the fractional part of a float number that contains .0. All other numbers are acceptable.. For example :
I/P: 1.0, 2.2, 88.0, 3.56666, 4.1, 45.00 , 99.560 O/P: 1 , 2.2, 88, 3.567, 4.1, 45 , 99.560
Is there any method available to do that other than “comparing number with “.0” and taking substring” ?
EDIT : I don’t want ACTING FLOAT NUMBERs (like 1.0, 2.0 is nothing but 1 2 right?)
I feel my question is little confusing…
Here is my clarification: I just want to display a series of floating point numbers to the user. If the fractional part of a number is zero, then display only the integer part, otherwise display the number as it is. I hope it’s clear now..
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Answer
You could use a regular expression such as this: \.0+$
. If there are only 0’s after the decimal point this regular expression will yield true.
Another thing you could do is something like so:
float x = 12.5; float result = x - (int)x; if (result != 0) { //If the value of `result` is not equal to zero, then, you have a decimal portion which is not equal to 0. }