I need to run a Spring Boot app using different configuration files. In local I can do it with the following JVM Option:
-Dspring.profiles.active=e1
What’s the way to do this when I run the app from a Jenkins job?
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Answer
With the assumption that user knows .jenkins file, I provide below the code snippet.
node { .... Other code stage("development") { withEnv(['JENKINS_NODE_COOKIE=someName']) { sh 'nohup ./mvnw spring-boot:run -Dspring.profiles.active=e1 &' } } }
For more details and reference, check below the link. https://www.baeldung.com/jenkins-pipelines
If you do not want to write .jenkins file, you can follow the link and setup manually. https://medium.com/finoit/continues-integration-using-jenkins-for-java-spring-4439ecd23bec
In case of gradlew clean build, you can provide the the following command.
mvnw spring-boot:run -Dspring.profiles.active=e1