I want to find vowels positions in the string. How can I make shorter this code?
I tried contains and indexOf method but couldn’t do it.
JavaScript
x
String inputStr = "Merhaba";
ArrayList<Character> vowelsBin = new ArrayList<Character>(Arrays.asList('a', 'e', 'i', 'o', 'u'));
ArrayList<Integer> vowelsPos = new ArrayList<Integer>();
for (int inputPos = 0; inputPos < inputStr.length(); inputPos = inputPos + 1)
for (int vowelPos = 0; vowelPos < vowelsBin.size(); vowelPos = vowelPos + 1)
if (inputStr.charAt(inputPos) == vowelsBin.get(vowelPos)) vowelsPos.add(inputPos);
return vowelsPos;
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Answer
I assume you want to get m2rh5b7
from your input string Merhaba
based on your code, then the below works fine,
JavaScript
String input = "Merhaba";
StringBuilder output = new StringBuilder();
for(int i = 0; i < input.length(); i++){
char c = input.toLowerCase().charAt(i);
if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u'){
output.append(i+1);
} else {
output.append(c);
}
}
System.out.println(output); // prints --> m2rh5b7
Or if you want just position of the vowels position only, the below is fine,
JavaScript
String input = "Merhaba";
for(int i = 0; i < input.length(); i++){
char c = input.toLowerCase().charAt(i);
if(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u'){
System.out.println(i);
}
}
you can use regex also, please refer the above from Alias.