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How to determine how many times a character is repeated in a string?

I am having some trouble with writing a method that when prompted with a number returns how many times each value is repeated. For example, if the number 7846597 is entered the method would return:

0 - 0
1 - 0
2 - 0
3 - 0
4 - 1
5 - 1
6 - 1
7 - 2
8 - 1
9 - 1

I know this would be most easily done with a loop, but I am not sure how to write the actual code. I also know that I need to convert the number value I get as an input into a string so I can use char methods.

This is my attempt:

public double countOccurences(int num)
{
    String str = num + "";
    int goneThrough = 0;
    int count0 = 0;
    int count1 = 0;
    int count2 = 0;
    int count3 = 0;
    int count4 = 0;
    int count5 = 0;
    int count6 = 0;
    int count7 = 0;
    int count8 = 0;
    int count9 = 0;
    while(goneThrough <= str.length())
    {
        int value = 0;
        if(value >= 10){
            value = value * 0;
        }
        if(str.charAt(0) == 0)
            count0++;
        if(str.charAt(0) = 1)
            count1++;
    }
    return count0;
    return count1;
    return count2;
    return count3;
    return count4;
    return count5;
    return count6;
    return count7;
    return count8;
    return count9;
}

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Answer

countOccurences(int num) should return the number of occurrences of each digit as int[10].

static int[] countOccurences(int num) {
    int[] result = new int[10];
    for ( ; num > 0; num /= 10)
        ++result[num % 10];
    return result;
}

public static void main(String[] args) {
    int input = 7846597;
    int[] output = countOccurences(input);
    for (int i = 0; i < 10; ++i)
        System.out.println(i + " - " + output[i]);
}

output:

0 - 0
1 - 0
2 - 0
3 - 0
4 - 1
5 - 1
6 - 1
7 - 2
8 - 1
9 - 1
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