How do I get the `.class` attribute from a generic type parameter?

The accepted answer to this question describes how to create an instance of T in the Generic<T> class. This involves passing in a Class<T> parameter to the Generic constructor and callin the newInstance method from that.

A new instance of Generic<Bar> is then created, and the parameter Bar.class is passed in.

What do you do if the generic type parameter for the new Generic class is not some known class like Bar but is itself a generic type parameter? Suppose I had some other class Skeet<J> and I wanted to create a new instance of Generic<J> from inside that class. Then, if I try to pass in J.class I get the following compiler error:

cannot select from a type variable.

Is there any way around this?

The specific bit of code triggering the error for me is:

public class InputField<W extends Component & WidgetInterface>
                                                 extends InputFieldArray<W>
{
  public InputField(String labelText)
  {
    super(new String[] {labelText}, W.class);
  }
  /* ... */
}

public class InputFieldArray<W extends Component & WidgetInterface>
                                                                 extends JPanel
{
   /* ... */
  public InputFieldArray(String[] labelText, Class<W> clazz)
                          throws InstantiationException, IllegalAccessException
  {
    /* ... */

    for (int i = 0 ; i < labelText.length ; i++) {
      newLabel = new JLabel(labelText[i]);
      newWidget = clazz.newInstance();
      /* ... */
    }
    /* ... */
  }
  /* ... */
}

The error happens, because I can’t write W.class. Is there some other way of passing in the same information?

Answer

Using .class on a type parameter isn’t allowed – because of type erasure, W will have been erased to Component at runtime. InputField will need to also take a Class<W> from the caller, like InputFieldArray:

public InputField(String labelText, Class<W> clazz)
{
    super(new String[] {labelText}, clazz);
}

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Answer