I am registering a filter as shown below For log output
i want url pattern : /*/api/*
@Bean public CommonsRequestLoggingFilter commonsRequestLoggingFilter() { CommonsRequestLoggingFilter filter = new CommonsRequestLoggingFilter(); filter.setIncludeClientInfo(true); filter.setIncludeHeaders(true); filter.setIncludePayload(true); filter.setIncludeQueryString(true); filter.setMaxPayloadLength(1000); return filter; } @Bean public FilterRegistrationBean filterRegistrationBean () { final FilterRegistrationBean registrationBean = new FilterRegistrationBean(); registrationBean.addUrlPatterns("/*/api/*"); return registrationBean; }
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Answer
Since the code registers a Servlet Filter
, the URL pattern must conform to the URL mappings supported by Servlets/Filters, as specified in the Servlet Specification:
12.2 Specification of Mappings
In the Web application deployment descriptor, the following syntax is used to define mappings:
A string beginning with a
/
character and ending with a/*
suffix is used for path mapping.A string beginning with a
*.
prefix is used as an extension mapping.The empty string (“”) is a special URL pattern that exactly maps to the application’s context root, i.e., requests of the form
http://host:port/<context-root>/
. In this case the path info is/
and the servlet path and context path is empty string (““).A string containing only the
/
character indicates the “default” servlet of the application. In this case the servlet path is the request URI minus the context path and the path info is null.All other strings are used for exact matches only.
So, a URL can have only one wildcard, and it must be first or last:
/some/path/*
*.ext