Check if array Is235

I want to check if an array Is235. Is235 is an array that has an integer divisible by 2, another integer divisible by 3 and a third integer divisible by 5. The other integers in the array that aren’t divisible by either of 2, 3, or 5 when added to the integers divisible by 2, 3 and 5 should be equal to the total number of elements in the array. Return 1 if the array Is235, else return 0. Please note that array cannot contain negative integers or zero. I want to approach this in a brute force manner only, thanks for your help in advance. My wrong attempt –

public class Array {

    public static void main(String[] args) {

        int[] arr = {2, 3, 5, 7, 11};

        System.out.println(is235Array(arr));
    }

    public static int is235Array(int[] a) {
        int n = a.length;
        int countOne = 0;
        int countTwo = 0;

        for (int i = 0; i < a.length; i++) {
            if (a[i] / 2 == 0 || a[i] / 3 == 0 || a[i] / 5 == 0) {
                countOne++;
            }
        }
        for (int j = 0; j < a.length; j++) {
            if (a[j] / 2 != 0 || a[j] / 3 != 0 || a[j] / 5 != 0) {
                countTwo++;
            }
        }
        if (countOne + countTwo != n) {
            return 0;
        }
        return 1;
    }
}

My countOne and countTwo variables couldn’t count the integers as i taught it would.

Answer

Try this, I tested it and it works, you should use the remainder operator %:

public class Array {

    public static void main(String[] args) {

        int[] arr = {2, 3, 5, 7, 11};

        System.out.println(is235Array(arr));
    }

    public static int is235Array(int[] a) {
        int countOne = 0;
        int countTwo = 0;

        for (int i : a) {
            if (i % 2 == 0 || i % 3 == 0 || i % 5 == 0) {
                countOne++;
            }else{countTwo++;}
        }

        if (countOne + countTwo != a.length) {
            return 0;
        }else{return 1;}

    }
}