Calculating the difference between max of even numbers and min of odd numbers of an array

The question statement says – You are given an array of integers A of size N. Return the difference between the maximum among all even numbers of A and the minimum among all odd numbers in A.

Examples – A = [5, 17, 100, 1] – Ans => 100-1 = 99

My Approach –

public class Solution {
    public int solve(int[] A) {
        int n = A.length;
        Arrays.sort(A);
        int max = 0;
        int min = 0;
        for(int i=n-1; i>=0; i--) {
            int max1 = A[i];
            if(max1%2 == 0) {
                max = max1;
                break;
            }
        }
        for(int i=0; i<n; i++) {
            int min1 = A[i];
            if(min1%2 == 1) {
                min = min1;
                break;
            }
        }
        int d = max-min;
        return d;
    }
}

The code is working fine for all input values other than negatives and I don’t know why? Can somebody help me?

Answer

You can write code like this. I change a little your code.

public int solve(int[] arr) {
    int n = arr.length;
    Arrays.sort(arr);
    int max = 0;
    int min = 0;
    for(int i=n-1; i>=0; i--) {
        if(arr[i]>max && arr[i]%2==0) {
            max = arr[i];
        }
    }
    for(int i=0; i<n; i++) {
        if(arr[i]<min && arr[i]%2!=0) {
            min= arr[i];
        }
    }
    int d = max-min;
    return d;
}

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Answer