needing help understanding this array method call [closed]

I just learned recently arrays. This exercise calls to return an average. I am trying to figure out how to return an average from this method call.

public class Numbers {
   
   // calcAverage() takes in an int array and returns the average value of elements in the array as a double.
   public double calcAverage(int[] nums) {
     
  
   }
   
   public static void main(String[] args) {
      Numbers numObject = new Numbers();
      int [] nums = {1,2,3,4,5};
      System.out.println(numObject.calcAverage(nums)); 
   }
}

The following code resolved the issue:

package testingCode;

public class test {

public double calcAverage(int[] nums) {

    double sum;
    int i;
    
    
    sum = 0;
    
    for (i = 0; i < nums.length; i++) { 
        
        sum = sum + nums[i];
        
    }
    
    sum = sum / nums.length;
    
    
    
return sum;

   }

public static void main(String[] args) {
    
    test numObject = new test();
      int [] nums = {1,2,3,4,5};
      System.out.println(numObject.calcAverage(nums)); 
      
      
      

}

}

Answer

// calcAverage() takes in an int array and returns the average value of elements in the array as a double.

public double calcAverage(int[] nums) {
    int sumOfElements=0;

    for (int num: nums){
        sumOfElements+=num;
    }
    return sumOfElements/(double)nums.length;
}

So the algorithm looks like:

1. Iterate over all elements in array to create the sum of them.
2. Divide the sum of the elements by the total number of elements. Attention! As both are integers it would be an integer division without decimal numbers. (That is why I cast the length to a double)