Let consider a hashmap
Map<Integer, List> id1 = new HashMap<Integer,List>();
I inserted some values into both hashmap.
For Example,
List<String> list1 = new ArrayList<String>();
list1.add("r1");
list1.add("r4");
List<String> list2 = new ArrayList<String>();
list2.add("r2");
list2.add("r5");
List<String> list3 = new ArrayList<String>();
list3.add("r3");
list3.add("r6");
id1.put(1,list1);
id1.put(2,list2);
id1.put(3,list3);
id1.put(10,list2);
id1.put(15,list3);
Q1) Now I want to apply a filter condition on the key in hashmap and retrieve the corresponding value(List).
Eg: Here My query is key=1, and output should be ‘list1’
I wrote
id1.entrySet().stream().filter( e -> e.getKey() == 1);
But I don’t know how to retrieve as a list as output of this stream operation.
Q2) Again I want to apply a filter condition on the key in hashmap and retrieve the corresponding list of lists.
Eg: Here My query is key=1%(i.e key can be 1,10,15), and output should be ‘list1′,’list2’,’list3′(list of lists).
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Answer
If you are sure you are going to get at most a single element that passed the filter (which is guaranteed by your filter), you can use findFirst
:
Optional<List> o = id1.entrySet()
.stream()
.filter( e -> e.getKey() == 1)
.map(Map.Entry::getValue)
.findFirst();
In the general case, if the filter may match multiple Lists, you can collect them to a List of Lists :
List<List> list = id1.entrySet()
.stream()
.filter(.. some predicate )
.map(Map.Entry::getValue)
.collect(Collectors.toList());