I have to use this as a switch statement. This is a switch statement, right?
if (dGrade > 93.99) {strFGrade= strA;} //A= above 94
else if (dGrade >= 90.00 && dGrade <= 93.99 ) {strFGrade= strLA;} //A- = 90-93.99
else if (dGrade >= 87.70 && dGrade <= 89.99) {strFGrade= strHB;} //B+= 87.7-89.99
else if (dGrade >= 83.33 && dGrade <= 87.69) {strFGrade= strB;} //B= 83.33-87.69
else if (dGrade >= 80.00 && dGrade <= 83.32 ) {strFGrade= strLB;} //B- = 80-83.32
else if (dGrade >= 75.00 && dGrade <= 79.99 ) {strFGrade= strHC;} //C+= 75-79.99
else if (dGrade >= 70.00 && dGrade <= 74.99 ) {strFGrade= strC;} //C= 70-74.99
else if (dGrade >= 60.00 && dGrade <= 69.99 ) {strFGrade= strD;} //D=60-69.99
else {strFGrade= strF;} //F= below 60
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Answer
No, it’s not possible to test if a value lies in an interval like this with a switch-statement. Switch-statements have one branch for each individual value of a type, and the branch is taken if the value being switch on is equal to that of the branch.
That being said, it is possible to write your code in a bit more compact way like this:
if (dGrade >= 94.00) strFGrade = strA; else if (dGrade >= 90.00) strFGrade = strLA; else if (dGrade >= 87.70) strFGrade = strHB; else if (dGrade >= 83.33) strFGrade = strB; else if (dGrade >= 80.00) strFGrade = strLB; else if (dGrade >= 75.00) strFGrade = strHC; else if (dGrade >= 70.00) strFGrade = strC; else if (dGrade >= 60.00) strFGrade = strD; else strFGrade = strF;
The trick here is that you can leave out half of the tests because you have already tested that in an earlier if-statement. This does not take into account that values could lie between the limits of two different intervals in the original code.
The blocks (with { and }) are also not necessary here.
And note the conventional white space usage, with space on both sides of the =.