Arrays variable in java [closed]

I am new to array concept there is something i cant understand that is i have read somewhere that when we intialize an array like int[] a = {1,2,3,4} ;

then a actually contain the address of memory location of the the first element of that array I havent statrted oop yet but as i know when toString method is used on reference variables it converts the value of an object that the reference variable contains its address to string but why when use

System.out.print(Arrays.toString(a));

the whole array is printed rather than just first element of array a ? because array a contains the address of first element only

Answer

The array was printed because you called Arrays.toString(int[] a) method
Which is implemented by JAVA API
https://docs.oracle.com/javase/7/docs/api/java/util/Arrays.html#toString(int[])

/**
 * Returns a string representation of the contents of the specified array.
 * The string representation consists of a list of the array's elements,
 * enclosed in square brackets (<tt>"[]"</tt>).  Adjacent elements are
 * separated by the characters <tt>", "</tt> (a comma followed by a
 * space).  Elements are converted to strings as by
 * <tt>String.valueOf(int)</tt>.  Returns <tt>"null"</tt> if <tt>a</tt> is
 * <tt>null</tt>.
 *
 * @param a the array whose string representation to return
 * @return a string representation of <tt>a</tt>
 * @since 1.5
 */
public static String toString(int[] a) {
    if (a == null)
        return "null";
    int iMax = a.length - 1;
    if (iMax == -1)
        return "[]";

    StringBuilder b = new StringBuilder();
    b.append('[');
    for (int i = 0; ; i++) {
        b.append(a[i]);
        if (i == iMax)
            return b.append(']').toString();
        b.append(", ");
    }
}

For more clarity related to arrays memory representations,
Kindly check the below diagram: