Java – Counting numbers in array

I’ve written a java prog that stores some values:

public class array05 {
    public static void main(String[] args) {

        //placement of value
        int arryNum[] = {2,3,4,5,4,4,3};

        //placement of index, to start at 0
        for(int counter=0;counter<arryNum.length;counter++){
            System.out.println(counter + ":" + arryNum[counter]);
        }
    }   
}

which generate such output:
0:2
1:3
2:4
3:5
4:4
5:4
6:3

and now I need to count numbers in this output #1. Output #2 should be this:

1: 0
2: 1
3: 2
4: 3
5: 1

It means it counts ONE 2, TWO 3, THREE 4, and only One 5.

I am not sure how to write the code for output 2. Is a binary search needed here?

can anybody shed a light?

Answer

if you are expecting in your array values between 1-5 (i assuming this from your expected output)

int arryNum[] = { 2, 3, 4, 5, 4, 4, 3 };
int[] counter = new int[] { 0, 0, 0, 0, 0 };
for (int i = 0; i < arryNum.length; i++) {
    counter[arryNum[i] - 1]++;
}

for (int i = 0; i < counter.length; i++)
    System.out.println((i + 1) + ":" + counter[i]);