I want to remove a string at the beginning of another.
Example:
| Begin | Removed | Final |
|---|---|---|
| “n123 : other” | Yes | other |
| “123 : other” | No | Error |
| “n4 : smth” | Yes | smth |
| “123 : a” | No | Error |
Thanks to Regexr, I made this regex:
/[\][n](?:[0-9]*)[ ][:]/g
I tried to use it in Java. With string.matches() I don’t have any error. But, with string.replaceFirst, I have this error :
java.util.regex.PatternSyntaxException: Unclosed character class near index 24
/[][n](?:[0-9]*)[ ][:]/g
^
What I tried else ?
- Remove
/at begin and/gat end. - Add
(pattern)(such as visible in regex here) - Multiple others quick way, but I the error is always at the last char of my regex
My full code:
String str = "n512 : something"; // I init my string
if(str.matches("/[\][n](?:[0-9]*)[ ][:]/g"))
str = str.replaceFirst("/[\][n](?:[0-9]*)[ ][:]/g", "");
How can I fix it ? How can I solve my regex pattern ?
Advertisement
Answer
You can use
.replaceFirst("n[0-9]+\s+:\s*", "")
The regex matches
n– a newline char (you have a newline in the string, not a backslash andn)[0-9]+– one or more digitss+– one or more whitespaces:– a colons*– zero or more whitespaces
See the Java demo:
List<String> strs = Arrays.asList("n123 : other", "123 : other", "n4 : smth", "123 : a");
for (String str : strs)
System.out.println(""" + str.replaceFirst("n[0-9]+\s+:\s*", "") + """);
Output:
"other" "123 : other" "smth" "123 : a"